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⁞ Electrical and Electronics Engineering

Engineering ➤ Electrical and Electronics Engineering ➤ Ohms-Law
Question 6
Q6.  When there is 12 mA of current through a 1.2 kΩ resistor, the voltage across the resistor is
 

Answer :  14.4 V


V = IR (Ohms Law)
= 12 × 10-3 × 1.2 × 103
= 12 × 1.2
= 14.4 V
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Question 7
Q7.  The current through a flashlight bulb is 40 mA and the total battery voltage is 4.5 V. The resistance of the bulb is approximately
 

Answer :  112 Ω


No Explanation available for this question. Let us Discuss.
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Question 8
Q8.  A resistance of 3.3 MΩ is connected across a 500 V source. The resulting current is approximately
 

Answer :  151 μA


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Question 9
Q9.  If 24 V are applied across a resistor and there are 10.9 mA of current, the resistance is
 

Answer :  2.2 kΩ


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Question 10
Q10.  If 750 μA is flowing through 11 kΩ of resistance, what is the voltage drop across the resistor?
 

Answer :  8.25 V


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